Micro & Immunology · single question

Which event occurs EARLIEST in the HIV replication cycle?

  1. Integration of viral DNA into the host genome
  2. Protease-mediated cleavage of the viral polyprotein
  3. Transcription of viral RNA from the provirus
  4. Reverse transcription of viral RNA into DNA
Show answer and explanation

Correct answer: D. Reverse transcription of viral RNA into DNA

  • A. Integration follows reverse transcription — the newly made DNA must exist before integrase can splice it into the host genome as a provirus. This step is the reason HIV infection is lifelong.
  • B. Protease cleavage is one of the LAST steps, occurring during and after budding to convert immature non-infectious particles into mature infectious virions.
  • C. Transcription of viral RNA from the integrated provirus occurs only after integration and uses host RNA polymerase II.
  • D. CORRECT. Of the four listed, reverse transcription comes first. After gp120 binds CD4 and a co-receptor (CCR5 or CXCR4) and the viral envelope fuses with the cell membrane, the core enters the cytoplasm and reverse transcriptase converts single-stranded viral RNA into double-stranded DNA. This enzyme has no proofreading capacity, which is the reason HIV mutates so rapidly and why combination therapy is necessary.

Note: Sequence: attachment → fusion → uncoating → REVERSE TRANSCRIPTION → integration → transcription → translation → assembly → budding → protease maturation. Each step is a drug target, which is a reliable way to remember the order: entry inhibitors (maraviroc), NRTIs and NNRTIs (reverse transcription), integrase inhibitors (dolutegravir), protease inhibitors (ritonavir).

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